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12x^2+1080x-21600=0
a = 12; b = 1080; c = -21600;
Δ = b2-4ac
Δ = 10802-4·12·(-21600)
Δ = 2203200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2203200}=\sqrt{129600*17}=\sqrt{129600}*\sqrt{17}=360\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1080)-360\sqrt{17}}{2*12}=\frac{-1080-360\sqrt{17}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1080)+360\sqrt{17}}{2*12}=\frac{-1080+360\sqrt{17}}{24} $
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